A die used in a certain board game has eight faces, of which 3 are red, 3 are yellow, and 2 are blue Each face is equally likely to and facup when the die is tossed in the game, player to the den ble lands faceup, and the number of fosses before blue and face is counted. For example, a player who tosses the sequence shown in the following table has tossed the die 3 times before burlands face 1 2 4 Toss number Face color yellow yellow red blue What is the probability that a player wil toss the die at least 2 times before blue landsfe?

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

the answer is two. hope this !