10 Tommy was trying to solve the system of a linear equation and a quadratic equation shown below.
2x - y = -1
x2 - 5x - y = -7
Tommy had completed the following steps in his algebraic solution process but could not factor
the resulting quadratic, x2 - 7x - 1, to complete the problem.
Step 1: y = 2x + 1
Step 11: 2 - 5x - (2x + 1) = -7
Step III: 2 5x + 2x + 1 = -7
Step IV: 2 - 7x-1 = -7
G
Determine the step in which Tommy made his mistake and justify your reasoning.
FStep 1: Tommy should have transformed the first equation to y = 2x - 1)
Step II, Tommy should have substituted the expression 2x + 1 in for each variable.
H Step III; Tommy should have distributed into the parentheses yielding the equation 2 - 5x
2x + 1 = -7.
J Step IV; Tommy must set the quadratic expression equal to 0 before factoring,

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

idk the answer but just put a

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.