What is the 98th term of the arithmetic sequence 29,9,-11

-951

Step-by-step explanation:

an=a1+(n−1)d

\begin{gathered}29 = a_1 + (1-1)d\\29 = a_1\\9 = 29 + (2-1)d\\9 = 29 + d\\d = -20\\a_n = 29 -20 (n-1)\\a_n = 29 - 20n+20\\a_n = -20n + 49a_51 = -20(51) + 49 = -951\end{gathered}29=a1+(1−1)d29=a19=29+(2−1)d9=29+dd=−20an=29−20(n−1)an=29−20n+20an=−20n+49a51=−20(51)+49=−951

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: