How do you put f(8)=-1,f(6)=0 into point slop form?

y + 1 = -1/2(x - 8)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula:

Point-Slope Form: y - y₁ = m(x - x₁)  

Step-by-step explanation:

Step 1: Define

f(8) = -1 → Coordinate (8, -1)

f(6) = 0 → Coordinate (6, 0)

Step 2: Find slope m

Step 3: Write Function

Substitute into general form.

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step-by-step explanation:

the x's and the y's both go up the same amount each time, therefore it will be a linear function because it will go in a straight line when drawn on a graph.

hope this !