What is the equation of the line parallel to 3x + 5y = 11 that passes through the point (15, 4)? O y=5/3x-29
O y=5/3x-21
O y=-3/5x+5
o y=-3/5x+13

step-by-step explanation:

cats

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)