A softball team has 12 girls on it. The coach needs to arrange 9 girls for the batting order. If the lineup is selected at random, what is the probability that you will be the lead-off batter (the first person to bat)?

P = 1/12 = 0.083

Step-by-step explanation:

Out of the 12 girls, there will be only one that is the lead-off batter.

we can assume that this is the first being selected at random, then the probability that you will be the lead-off batter, is equal to the quotient between 1 (the outcome where you are selected) and 12 (the total number of outcomes)

Then the probability is:

P = 1/12 = 0.083

The fact that there will be an arrange of only 9 girls does not affect the probability of you getting the position of the lead-off batter.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.