Sydney has a bag of stuffed animals containing, 1 elephant, 4 bears, 3 cats, and 2 dogs. If she randomly selects 1 stuffed animal from the bag, places it on her bed and then selects another animal. What is the probability that she chooses a bear both times?

2/15

Step-by-step explanation:

Step one:

given data

sample space

1 elephant,

4 bears,

3 cats, and

2 dogs.

sample size= 1+4+3+2= 10

Required:

By selecting without replacement, the probability that she chooses a bear both times

Step two:

the first event= Pr(bear)= 4/10= 2/5

the second event, the sample size is now 9 and the number of bears is now 3

Pr(bear)= 3/9= 1/3

Hence, the probability that she chooses a bear both times

= 2/5*1/3

=2/15

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.