What is an equation of the line that passes through the point (−1,−3) and is parallel to the line 6x-y=1

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

i think the answer is 90 hope this

this equation is in point-slope form.

where,

using this equation you can gather a point and the slope, which gives you enough information to draw a line. transform the equation to standard form to start.

the equation is now in standard form, we have a point, as well as the slope:

point: (0, -6)

slope: -2

plot (0,-6), then simply rise/run with the provided slope of -2, once you feel you have a comfortable amount of points - draw a line.