Write as a single fraction in its simplest form 2x -1 / 3 - 2/x + 1

(2x^2 + x-7)/3x+ 3

Step-by-step explanation:

Here, we want to write the following as a single fraction;

2x-1/3 - 2/x + 1

That will be;

(2x-1)(x + 1) -2(3)/3(x+ 1)

= 2x^2+ 2x-x-1-6/3(x + 1)

= (2x^2+x-7)/3(x+1)

= (2x^2 + x-7)/3x+ 3

96 39 cause 135 -96=39 im smart (i used a calculater)

there is no graph so i cant sorry

step-by-step explanation: