find the length of sides in an isosceles triangle whose sides are 3x-0.4 & x+1.4 (equal sides) and not equal side is x+0.1

The length of the sides are;

2.3, 2.3 and 1

Step-by-step explanation:

If the equal sides are 3x-0.4 and x + 1.4

This means these two are equal to one another

Thus;

3x-0.4 = x + 1.4

3x-x = 1.4 + 0.4

2x = 1.8

x = 1.8/2

x = 0.9

So the length of the sides are as follows;

3x - 0.4

3(0.9)-0.4 = 2.3

x + 1.4

= 0.9 + 1.4 = 2.3

And lastly

x + 0.1

0.9 + 0.1 = 1

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

a

step-by-step explanation: