A teacher reaches into a bag of game pleces containing 5 black pleces, 3 purple pleces, 1 orange plece, and 6 green pleces, He draws 2 pleces, setting aside the first plece before drawing the second. What is the probability that at least one of the drawn pleces ls purple?

The probability of choosing a purple piece is 3/15, choosing an orange piece will be 1/15, that of black pieces is 5/15 and that of choosing a green piece is 6/15.
This would be PP + PW+ PG + PB +WP +GP + BP
= (3/15 × 2/14) + (3/15×1/14)+(3/15×6/14) +(3/15+5/14)+(1/15×3/14) + (6/15× 3/14) + (5/15 × 3/14)
= 6/210 +3/210 +18/210+15/210+3/210 +18/210+ 15/210
= 78/210
= 13/35

3x+9+4x+x=8x+9that's the answer for your question.

Idon’t feel like doing the math but you need to do 2.24 divided by 7