The relationship between altitude and the boiling point of a liquid is linear. At an altitude of 8100 ft, the liquid boils at 203.66 degrees F. At an altitude of 4700 ft, the liquid boils at 208.42 degrees F. Write an equation giving the boiling point b of the liquid, in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2600 ft?

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Step-by-step explanation:

We are given two points: (a, b) = (8100, 203.66) and (4700, 208.42). We can use these in the 2-point form of the equation for a line

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1 . . . . . . line through (x1, y1) and (x2, y2)

Using the given values, we have ...

  b = (208.42 -203.66)/(4700 -8100)(a -8100) +203.66

  b = 4.76/-3400(a -8100) +203.66

  b = -0.0014a +215 . . . . . simplify

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At 2600 ft, the boiling point is ...

  b = -0.0014(2600) +215 = 211.36 °F

answer: it's d

step-by-step explanation:

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry