Help please need help ASAP

g phone the other questions please let me that he had an amazing time to Suna tha wo boli kya mama I have a doctor and square footage clip for more details on Friday November this year and square footage clip and square footage of rectangular shape or comments regarding the questions that may arise in touch as soon I have received a sum of Plassey and sahi h jo the questions I had to the best of Plassey the questions. Aladdin Nam to Suna he hoga

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

a negative exponent is translated as follows:

so, we have