4. Bikes A and B are traveling on perpendicular roads. At the same time, bike A is leaving the intersection at a rate of 2 feet per second and bike B is leaving the
intersection at 3 feet per second. How fast is the distance, in feet per second between
them changing after 5 seconds?

answer: what are the answer choices?

step-by-step explanation:

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75

add the numbers under frequency to find the total number:

5 + 8 +7 + 4 + 0 +1 = 25

the answer is 25.

step-by-step explanation:

f(gx)=f(1/x+2)

=(1/x+2)+2

=(1+2x)/2+2

=(1+2x+4)/2

= (2x+5)/2