A spherical balloon is being deflated at a rate of 5 cubic centimeters per second. At what rate is the radius of the balloon changing at the instant the volume of the balloon 972pi cm^3?

0.0048cm/s

Step-by-step explanation:

Volume of the spherical balloon is expressed as;

dV/dt = dV/dr * dr/dt

Given

dV/dt = 5cm³/s

dV/dr = 4πr²

Since V = 972picm³

972π = 4/3πr³

972 = 4/3r³

4r³ = 972 * 3

r³ = (972 *3)/4

r³ = 729

r = ∛729

r = 9cm

dV/dr = 4π(9)²

dV/dr = 324π

dV/dt = dV/dr * dr/dt

5 = 324πdr/dt

dr/dt = 5/324π

dr/dt = 5/324(3.14)

dr/dt = 5/1017.36

dr/dt = 0.0048cm/s

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58