Slope 8 ; through (4,3)

I'm assuming you need to find the equation of that line.  If that's not what you need, you can stop here, because that's what I'm going to calculate.

When we're working with the equation of a line, we know it's easy to work with if it's in the form of a "slope / intercept" equation.

That's  Y = (slope) · x + (y-axis intercept)

We already know the slope of this line, because the question gave it to us.  The slope is ' 8 ' .  So we know the equation will be Y = 8x + (y-intercept) .

OK.  We also know a point on the line ... (4, 3).

That tells us:  When x=4 on this line, y=3 .

Take the equation, and put this point into it.

Y = 8x + (y-intercept)

(3) = 8(4) + y-intercept

3 = 32 + y-intercept

Subtract 32 from each side:

-29 = y-intercept

So the equation of the line is:  Y = 8x - 29

there are no short passages to look at

because they could drop even lower..