4a - 2(a + b) + 1 = ? a=2 b=4

a + b)2 = a2 + 2ab + b2

(a + b)3 = a3 + 3a2b + 3ab2 + b3

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

a2 - b2 = (a - b)(a + b)

a2 + b2 = (a - bi)(a + bi)

a3 - b3 = (a - b)(a2 + ab + b2)

a3 + b3 = (a + b)(a2 - ab + b2)

a4 + b4 = (a2 + √2ab + b2)(a2 - √2ab + b2)

an - bn = (a - b)(an-1 + an-2b + ... + bn-1), for n even

an + bn = (a + b)(an-1 - an-2b - ... - bn-1), for n odd

Step-by-step explanation:

idk

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.