Simplify the sum. d^2-5d+6/d^2+d-6 + d^2-4d-5/d^2+3d+2

B. (2d^2 - 3d-21)/((d+2)(d+3))

Step-by-step explanation:

(d^2 - 5d + 6)/(d^2 + d - d) + (d^2 - 4d-5)/(d^2+3d+2)

(d^2 - 5d + 6)/(d^2 + d - d) = (d-3)/(d+3)

(d^2 - 4d-5)/(d^2+3d+2) = (d - 5)/(d+2)

(d-3)/(d+3) + (d - 5)/(d+2)

Least common Multiplier of d + 3 and d + 2 is (d+3)(d+2)

((d-3)(d+2))/((d+3)(d+2)) + ((d-5)(d+3))/((d+2)(d+3))

((d-3)(d+2)+(d-5)(d+3))/((d+3)(d+2))

(2d^2 - 3d - 21)/((d+2)(d+3))

its 4 because 2 times 2 is 4, if you double the number two you get four

idk

step-by-step explanation: