Solve for r: -6+4r=2(r-4)
A) -1
B) 1
C) -12
D) 12

An advertisement is on a flyer that has a thickness of 8.2 × 10-5 meters. each measurement below is the thickness of a stack of flyers. drag each measurement to the correct stack.

2x + 1 < 5 solve the following inequality. then place the correct number in the box provided.

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane