The base of an isosceles triangle is 4 units longer than the sides. The perimeter of the triangle is 23.6 units. Which
system of equations can be used to find the length b of the
base and the length s of the sides?

Step-by-step explanation:

2s + b = 23.6

s + 4 = b

s = b - 4

2b - 8 + b = 23.6

3b = 31.6

b = 31.6 / 3 = 10.53333333(etc.) which is approx. 10.53

s = 6.53

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

Step-by-step explanation:

hope this .

r3t40

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3