If you have less than $10.00 in dimes and quarters. Which of the following is a possible combination of dimes and quarters that satisfy the inequality. *
a. 50 dimes and 20 quarters
b. 20 dimes and 50 quarters
c. 50 dimes and 30 quarters
d. 40 dimes and 20 quarters

D. 40 dimes and 20 quarters

Step-by-step explanation:

40 dimes= $4 because 10 dimes= $1

20 quarters= $5 because 4 quarters= $1

The other options are above $10. I hope this helps :D

step-by-step explanation:

f

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240