3х + 4 = 14
х = 2y - 12

(-2, 5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

3x + 4y = 14

x = 2y - 12

Step 2: Solve for y

Substitution

Substitute in x:                    3(2y - 12) + 4y = 14Distribute 3:                         6y - 36 + 4y = 14Combine like terms:           10y - 36 = 14Isolate y term:                     10y = 50Isolate y:                              y = 5

Step 3: Solve for x

Define equation:                    x = 2y - 12Substitute in y:                       x = 2(5) - 12Multiply:                                  x = 10 - 12Subtract:                                 x = -2