What is the 7th term of the geometric sequence where a1 = 1,024 and a4 = -16?

The solution to your problem is as follows:

First term, a = 1024 
Common ratio, r = –16 /1024  = –0.02 
7th term = 1024 ( –0.02 ) ^ ( 7 - 1 ) 
= 1024 ( –0.02 ) ^ 6 
= 1024 ( 6.4E-11) 
= 6.5536E-8

Therefore, the 7th term of the geometric sequence is 6.5536E-8.

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Answer: r=4.5  feetexplanation: radius  r  is half of the diameter  d,⇒r=d2=92=4.5  feetidk i could be wrong