G(x)=x^2-4 f(x) = -2x-3
Find g(-6) – f(-6)

someone help and please show steps

23

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

g(x) = x² - 4

f(x) = -2x - 3

g(-6) is x = -6 for function g(x)

f(-6) is x = -6 for function f(x)

Step 2: Evaluate

g(-6)

Substitute in x:                    g(-6) = (-6)² - 4Exponents:                          g(-6) = 36 - 4Subtract:                              g(-6) = 32

f(-6)

Substitute in x:                    f(-6) = -2(-6) - 3Multiply:                               f(-6) = 12 - 3Subtract:                              f(-6) = 9

g(-6) - f(-6)

Substitute:                    32 - 9Subtract:                       23

This is too long-standing now get out

Answer x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​

step-by-step explanation: