What is the center and radius of the circle with the equation x2 + y2 + 8x – 12y + 36 = 0 ? . center: (5, 6); radius = 4. center: (–4, 6); radius = 5. center: (5, 6); radius = 5. center: (–4, 6); radius = 4.

The best and most correct answer among the choices provided by your question is the fourth choice which is "Center: (–4, 6); Radius = 4."

(x² + 8x) + (y² - 12y) = - 36 

(x² + 8x + 16) + (y² - 12y + 36) = - 36 + 16 + 16 

(x + 4)² + (y - 6)² = 16 

C (- 4 , 6 ) , r = 4

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