Which statements verify that the solution set to |x + 3| < 5 is –8 < x < 2? Check all that apply. Substituting a value into the inequality from the solution set, such as –2, will create a true statement. Substituting a value into the inequality from the solution set, such as 1, will create a false statement. Substituting a value into the inequality not from the solution set, such as 4, will create a true statement. Substituting a value into the inequality not from the solution set, such as 6, will create a false statement. Substituting any value into the inequality will create a true statement.

First and fourth statements are correct

Step-by-step explanation:

The function is where the domain is

The first statement is correct.

Substituting a value into the inequality from the solution set, such as 1, will create a false statement. This is wrong as it creates a true statement.

Substituting a value into the inequality not from the solution set, such as 4, will create a true statement. This is wrong as a value which is not from the solution set will create a false statement.

Substituting a value into the inequality not from the solution set, such as 6, will create a false statement. This is correct.

Substituting any value into the inequality will create a true statement. This is wrong as the value of x must be in the solution set.

the answer is 3/5

step-by-step explanation:

first divide 24 divided by 8 because that is the least common multiple

then divide 40 by 8

then you will get 3/5.

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)