This is what the problem says Assuming all parabolas are of the form y=ax^2+bx+c, drag and drop the graphs to match the appropriate a-value

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  graphs left to right have a=1, a=0.25, a=-1

Step-by-step explanation:

A negative value of 'a' makes the parabola open downward, so the rightmost graph goes with a=-1.

A value of 'a' less than 1 flattens the graph, so the middle graph goes with a=0.25.

A value of 1 gives a standard open-upward parabola, corresponding to the leftmost graph.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24