Each football costs the same amount, and each basketball costs the same amount. At the first store, the coach paid $110 for 5 footballs and 14 basketballs. At the second store, the coach paid $82.50 for 10 footballs and 6 basketballs. What was the cost in dollars of each basketball?

$6.25

Step-by-step explanation:

Each football costs the same amount, and each basketball costs the same amount.

Let the cost of:

Footballs = f

Basketballs = b

Hence, we have the following system of equations

At the first store, the coach paid $110 for 5 footballs and 14 basketballs.

5f + 14b = 110

At the second store, the coach paid $82.50 for 10 footballs and 6 basketballs.

10f + 6b = 82.50

What was the cost in dollars of each basketball?

5f + 14b = 110 Equation 1

10f + 6b = 82.50Equation 2

We solve using Elimination method.

Multiply Equation 1 by 10 and Equation 2 by 5 to eliminate f

50f + 140b = 1100 Equation 3

50f +30b = 412.5Equation 4

Subtract Equation 4 from Equation 3

110b = 687.5

b= 687.5/110

b = $6.25

Therefore, the cost of one basketball in dollars = $6.25

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10