During the first week of school Andrew purchased two pounds of Jellies and two pounds of Bonbons for $38. The second week of school he purchased two pounds of Jellies and four pounds of Chocolates for $74 and the third week he purchased two pounds of Jellies, two pounds of Bonbons and one pound of Chocolates for $53. What is the cost of one pound of Chocolates?

j = $7

b = $12

c = $15

Step-by-step explanation:

Let

j = cost of one pound of jelly

b = cost of one pound of Bonbon

c = cost of one pound of chocolate

First week:

two pounds of Jellies and two pounds of Bonbons for $38.

2j + 2b = 38

Second week:

two pounds of Jellies and four pounds of Chocolates for $74

2j + 4c = 74

Third week:

two pounds of Jellies, two pounds of Bonbons and one pound of Chocolates for $53.

2j + 2b + c = 53

Recall,

2j + 2b = 38

So,

38 + c = 53

c = 53 - 38

= 15

c = $15

Substitute c = 15 into

2j + 4c = 74

2j + 4(15) = 74

2j + 60 = 74

2j = 74 - 60

2j = 14

j = 14/2

= 7

j = $7

Substitute j = 7 into

2j + 2b = 38

2(7) + 2b = 38

14 + 2b = 38

2b = 38 - 14

2b = 24

b = 24/2

= 12

b = $12

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

mr. india