The mean June midday temperature in Desertville is 36C and the standard deviation is 3C. Assuming this data is normally distributed, how many days in June would you expect the middaytemperature to be between 39C and 42C

4

Step-by-step explanation:

Given that:

Mean temperature (m) = 36°C

Standard deviation (s) = 3°C

Temperature between 39°C and 42°C

Temperature < 39°

Probability of temperature < 39

P(x < 39)

The standardized score (Z) :

Z = (x - m) / s

Z = (39 - 36) / 3 = 1

p(Z < 1) = 0.84134 ( Z probability calculator)

Temperature < 42°

Probability of temperature < 42°

P(x < 42)

The standardized score (Z) :

Z = (x - m) / s

Z = (42 - 36) / 3 = 2

p(Z < 2) = 0.97725 ( Z probability calculator)

p(Z < 2) - p(Z < 1) = 0.97725 - 0.84134 = 0.13591

Hence, number of days in June = 30

Expected number of days = 30 * 0.13591 = 4.0773 = 4 (nearest whole number)

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: