A garden is in the shape of a right triangle. The two legs of the triangle measures 12 and 15. Find the perimeter of the garden

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .

Do,h = (7, 9) (14, 18) the scale factor is

Which spreadsheet would be used to compute the first nine terms of the geometric sequence a^n=32•(1/2)n-1