(X+4+1)(x+4)=(11+x+1)(x+1) solve for x

x= 2

Step-by-step explanation:

so you add the values given in the brackets and leave X as it is (do this on both sides of the equation.

1. (x + 5)(x+4)= (x+12)(x+1)

2. multiply the parenthesis on both sides or one at a time

so,  +5x+4x+20 = +12+1x+12

3. cancel like terms which we have so remove that.

5x+4x+20=12+1x+12

4. collect like terms.

9x + 20 = 13x + 12

5. move like terms.

9x-13x=12-20 = -4 = -8

6. x=  divide both sides by 4 or basically simplify 4 divided by 8

which leaves u with

x= 2

hope this helps x, let me know if u have any questions. photomath is an app that helps too.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.