ASAP Two sides of a triangle are given. Find the range of values for the third
side. (Answer as an inequality.)
6 and 14

Sides: a = 6   b = 9   c = 14

Area: T = 18.41

Perimeter: p = 29

Semiperimeter: s = 14.5

Angle ∠ A = α = 16.991° = 16°59'29″ = 0.297 rad

Angle ∠ B = β = 25.998° = 25°59'53″ = 0.454 rad

Angle ∠ C = γ = 137.011° = 137°39″ = 2.391 rad

Height: ha = 6.137

Height: hb = 4.091

Height: hc = 2.63

Median: ma = 11.38

Median: mb = 9.785

Median: mc = 3.082

Inradius: r = 1.27

Circumradius: R = 10.266

Vertex coordinates: A[14; 0] B[0; 0] C[5.393; 2.63]

Centroid: CG[6.464; 0.877]

Coordinates of the circumscribed circle: U[7; -7.509]

Coordinates of the inscribed circle: I[5.5; 1.27]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 163.009° = 163°31″ = 0.297 rad

∠ B' = β' = 154.002° = 154°7″ = 0.454 rad

∠ C' = γ' = 42.989° = 42°59'21″ = 2.391 rad

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

there is no graph so i cant sorry

step-by-step explanation: