The length of a rectangle is 6 yds longer than its width. If the perimeter of the rectangle is 72 yd, find its length and width.

I think

Let  L  represent length.

Let W  represent width.

Since the length is 6 yd longer than its width:  L  =  6 + W

The formula for perimeter:  P  =  2L + 2W  

Since the perimeter is 44 yds:     44  =  2L + 2W

Substituting:                             44  =  2(6 + W) + 2W

                                               44  =  12 + 2W + 2W

                                               44  =  12 + 4W

                                               32  =  4W

                                                W  =  8 yds

Since  L  =  6 + W  --->  L  =  14 yds

false

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step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)