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Mathematics, 10.12.2020 18:20 Franklyn3220

Factor the difference of cubes. x^3– 27=
A(x - 3)(xΒ² + 3x + 9) = 0
B (x + 4)(xΒ² + 3x +9) = 0
C(x - 3)(2.x2 + 3x + 9) = 0
D(X- 3)xΒ² + 3.8 + 7) = 0

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You know the right answer?
Factor the difference of cubes. x^3– 27=
A(x - 3)(xΒ² + 3x + 9) = 0
B (x + 4)(xΒ² + 3x +9...
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