Select one of the factors of x^2y^3 - 11x^2y + 6y^2 - 66.

a.) (x^2y + 6)
b.) (x^2y - 6)
c.) (y^2 + 11)
d.) (y - 3)

The correct answer is:

A.) (x^2y + 6)  

Explanation:

In order to factor this, we will use factoring by grouping.  To do this, we first break the polynomial into two groups by placing parentheses around the first two terms and around the second two terms:

(x²y³-11x²y)+(6y²-66)

Next, we factor out the GCF of each group.  For the first group, both terms have an x² and a y; there are no numbers in common (other than 1).  Factoring this out,

x²y(y²-11)+(6y²-66)

The GCF of the second group is 6, as both terms are divisible by 6:

x²y(y²-11)+6(y²-11)

We look to the remaining terms in parentheses.  If we have worked correctly, they should be the same.  They are.  This is now the GCF of the polynomial, since it is common to both terms:

(y²-11)(x²y+6)

man its nopq i just guessed and got it right so uhh

g00d lucc

step-by-step explanation:

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

i googled it and this is what i got i don't know how it is. sorry.