Fill in the blanks:

mark’s garden is a rectangle that is 4a^2 + 96a + 15 meters long and 4a^2 + 24a + 15 meters wide. if mark decides to fence his garden, the total length of fencing material required would be meters. if he uses prebuilt fence sections that are 50 centimeters wide, he will need .

So for a rectangle, perimeter = 2L + 2W. 

Plugging in, we get 

P = 2 [ (4a + 96) / (a + 15) ] + 2 [ (4a + 24) / (a + 15) ] 

= (8a + 192 + 8a + 48) / (a + 15) 

= (16a + 240) / (a + 15) 

= 16(a + 15) / (a + 15) 

= 16 meters. 

So if Mark buys the sections, 

50 cm = 0.5 meter, so he will need 32 sections.

I hope my answer has come to your help. Thank you for posting your question here in .

Find the perimeter of the figure shown above with a side length 5 units.(each figure is a square).a.10 unitsc.30 unitsb.20 unitsd.40 units select the best answer from the choices providedabcdmark this and return

Yes of course i will indeed you with your problem.