Two new student clubs start at a school. Each club has a plan to increase membership. Club
Start with 12 members, and grow by 4 members each week, w.
1
Club Start with 3 members, and double in total membership by the end of each
2.
week, w.
Which system of equations can be used to determine when the number of members, N, will be the same for each club?
N = 4 + 12
N = 2(3)"
N = 4 + 12
N = 3(2)"
N = 4x + 12
N = 2(3)"
N = 4w + 12
N = 3(2)"

The correct option is;

N = 4·w + 12

N =

Step-by-step explanation:

The given plan the clubs will use to increase membership are;

Club 1: The starting number of members in the club = 12

The number of additional members added each week = 4

Club 2: The starting number of members in the club = 3

The total number of members at the end of each week = Double the the initial total membership

Therefore, we have;

For club 1, N = 12 + 4×w = 4·w + 12

N = 4·w + 12

For club 2, at week w, N = 3 × 2 × 2 ×...× 2 =

The correct option is therefore, N = 4·w + 12, N =

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2