What is the distance from the origin to point P graphed on the complex plane below

b) √29

Step-by-step explanation:

Given: The origin is (0, 0), the point P is (2, -5).

We need to use the distance formula.

Distance formula =

Here x2 = 2, x 1 = 0, y1 =0, y2 = -5

Distance =

= √(4 + 25)

= √29

The answer is b) √29

Hope you will understand the concepts

Thank you!!

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead