Use the figure below to answer the question that follows: Intersecting triangles ACE and BDF. They intersect at points G, H, I, and J.

What must be given to prove that ΔBJI ~ ΔBDF
?

segment BH is congruent to segment CH and segment BG is congruent to segment CI
∠BIJ ≅ ∠CGJ and ∠JBI ≅ ∠JIB
segment BI is congruent to segment CG and segment JI is congruent to segment JG
∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG

b

step-by-step explanation:

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12

d is the only accurate one

step-by-step explanation: