Answer two questions about Systems A and B: System A:
x+3y=-99
2x+y=4
System B:
3x+4y=-9
2x+y=4
1) How can we get System B from System A?

A) Replace one equation with the sum/difference of both equations

B) Replace only the left-hand side of one equation with the sum/difference of the left-hand sides of both equations

C) Replace one equation with a multiple of itself

D) Replace one equation with a multiple of the other equation
2) Based on the previous answer, are the systems equivalent? In other words, do they have the same solution?
Choose 1
Choose 1
A)Yes
B)No

1) replace only the left-hand side of one equation with the sum/difference of both equations

2) no

Step-by-step explanation:

i just did this problem lol

1

step-by-step explanation:

it's the only multiple of both and the least

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: