At a movie theater, student tickets cost $6 each and adult tickets cost
$9 each. The theater sold 148 tickets
and made $1,188. How many adult
tickets did the movie theater sell?

65 student tickets were sold

Step-by-step explanations:

Given that movie theater sells student tickets for $ 6 and adults for $ 8

Let "s" be the number of student tickets sold

Let "a" be the number of adult tickets sold

Cost of 1 student ticket = $ 6

Cost of 1 adult ticket = $ 8

Given that theater sold 140 tickets

Number of student tickets sold + number of adult tickets sold = 140

s + a = 140 eqn 1

The theater generated $ 990

number of student tickets sold x Cost of 1 student ticket + number of adult tickets sold x Cost of 1 adult ticket = 990

6s + 8a = 990 eqn 2

Let us solve eqn 1 and eqn 2 to find values of "s" and "a"

From eqn 1,

s = 140 - a eqn 3

Substitute eqn 3 in eqn 2

6(140 - a) + 8a = 990

840 - 6a + 8a = 990

2a = 150

a = 75

Substitute a = 75 in eqn 3

s = 140 - 75

s = 65

Therefore 65 student tickets were sold

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.