Jayden has $0.56 worth of pennies and nickels. He has a total of 20 pennies and nickels altogether. Determine the number of pennies and the number of nickels that Jayden has.

11 pennies and 9 nickels

Step-by-step explanation:

Set up a system of equations where p is the number of pennies and n is the number of nickels:

p + n = 20

0.01p + 0.05n = 0.56

Solve by substitution by rearranging the first equation:

p + n = 20

p = 20 - n

Then, plug this in as p into the second equation, and solve for n:

0.01p + 0.05n = 0.56

0.01(20 - n) + 0.05n = 0.56

0.2 - 0.01n + 0.05n = 0.56

0.2 + 0.04n = 0.56

0.04n = 0.36

n = 9

Then, plug this into the first equation to solve for p:

p + n = 20

p + 9 = 20

p = 11

So, Jayden has 11 pennies and 9 nickels

its not b

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !