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Mathematics, 10.12.2020 02:50 zoeycrew

Please help for brainliest imbegging you this is confsiusing to me The work of a student to solve the equation 4(2x โˆ’ 4) = 8 + 2x + 8 is shown below:

Step 1: 4(2x โˆ’ 4) = 8 + 2x + 8

Step 2: 6x โˆ’ 8 = 16 + 2x

Step 3: 6x โˆ’ 2x = 16 + 8

Step 4: 4x = 24

Step 5: x = 6

In which step did the student first make an error and what is the correct step?

Step 2; 8x โˆ’ 4 = 2(6 + x + 6)

Step 2; 8x โˆ’ 16 = 16 + 2x

Step 3; 6x โˆ’ 2x = 16 โˆ’ 8

Step 3; 6x + 2x = 16 + 8

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