Answers: 2
![f^{-1}(x)=\dfrac{\sqrt[3]{x}+1}{2}}](/tpl/images/0967/9223/465df.png)
![x=(2y-1)^3\\\\\sqrt[3]{x}=2y-1\qquad\text{take cube root}\\\\\sqrt[3]{x}+1=2y\qquad\text{add 1}\\\\y=\dfrac{\sqrt[3]{x}+1}{2}\qquad\text{divide by 2}\\\\\boxed{f^{-1}(x)=\dfrac{\sqrt[3]{x}+1}{2}}](/tpl/images/0967/9223/32d87.png)
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