A city bus collected $1,140 in fares on a given day. The regular fare is $1.50, and the reduced fare is $0.75. If 1,042 total fares were paid which system of linear equations can be used to find x, the number of regular fares paid, and y, the number of reduced fares paid

x + y = 1042

1.50x + 0.75y = 1140

Step-by-step explanation:

If there was a total of 1,042 fares paid then x + y would be equal to that because x is the number of regular fares paid and y is the number of reduced fares paid.

If there was a total of $1,140 made from the fares then we can use 1.50x + 0.75y. We put the 1.5 in front of the x because each fare paid costs $1.50, same with Y each reduced fare paid is $0.75. So both of those need to be added up to get $1,140.

If you need question solved, like to find x and y, let me know.

I hope this helps!

- Kay :)

x + y = 1042

1.50x + 0.75y = 1140

Step-by-step explanation:

so what is the question

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )