Questions 1-8 of 8 Page 1 of 1 Question 1 (1 point)
Chan is throwing a ball from the ground at an initial velocity of 22.1 meters per seconds. He threw the ball so high that on it's way down it
got stuck in a tree 10 meters high. How long was the ball in the air before it got stuck in the tree?

9514 1404 393

  4.0 seconds

Step-by-step explanation:

The equation for ballistic motion is ...

  y = -4.9t^2 +22.1t

We want to find the larger value of t that makes y = 10.

  10 = -4.9t^2 +22.1t

  4.9t^2 -22.1t +10 = 0

Using the quadratic formula, we have ...

  t = (22.1 + √(22.1² -4(4.9)(10)))/(2·4.9) = (22.1 +√292.41)/9.8 = 39.2/9.8

  t = 4

The ball was in the air 4 seconds before it got stuck.

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

the least common denominator is 40