A volleyball was passed from one player to another with an initial velocity of 28 feet per second from an initial height of 3 feet. The function h(x) = -16x2 + 28x + 3 models the height, in feet, of the volleyball x seconds after it was passed. What was the maximum heigh
of the volleyball?

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629

the clb she uses is a driver, so its a 2/5 chance she hits a 180-189 yard shot

step-by-step explanation: