T:
+
1
1
1
1 + xa + x-b 1 + x + x-
1 + xb + x-c ' 1 + x + x-a
= 1
+

is this a real equation?

Step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: