Miya flips a coin and rolls a 6-sided number cube labled 1-6 and records tge outcome. About how many times is she likely to flip heads and roll a 3 out of 48 trials

4 times

Step-by-step explanation:

Sample space :

6 sided cube = (1, 2, 3, 4, 5, 6)

Coin = (H, T)

Probability = required outcome / Total possible outcomes

Probability of head (H) = P(H) = 1 /2 = 0.5

Probability of 3 = P(3) = 1 /6 = 0.166666

Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333

Hence, expected number of times this is likely to occur in 48 tries :

0.083333 * 48 = 4

step-by-step explanation:

b and c

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.